خرید بک لینک

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1st part:

i=j=k=1;
m = ++i && ++j || ++k;
printf("%d, %d, %d, %dn", i, j, k, m);

output: 2, 2, 1, 1

1st part easily understood ,Here ++i && ++j execute first, which is true (and increment value of i and j) so there is no need to check next part of OR operation(no need increment value of k) .

2nd part:

i=j=k=1;
m = ++i || ++j && ++k;
printf("%d, %d, %d, %dn", i, j, k, m);

output: 2, 1, 1, 1

2nd part confusing to understand ,Here ++i || ++j execute first, in which ++i is true (and increment value of i, since OR opreation so no need to increment value of j ). Next execute AND operation here should be increment value of k=2(but still value of k print 1).

Dear altruist, please explain me what happen in 2nd part.

asked 30 secs ago

برچسب: نویسنده: استخدام کار تاريخ: جمعه 15 مرداد 1395 ساعت: 1:50

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