I want to pass a string with whitespaces as a variable to awk from a Bash script, but independent of how I escape it, awk will complain. Please consider the following example:
list1:
one
two
three
four
The output:
[user@actual ~]$ ./dator.sh list1
1470054866 two (...)
A working script:
CMD='awk'
DATE=$(date +%s)
VARIABLES="-v time=$DATE"
SCRIPT='NR>=2 {printf "%s %sn", time, $1;}'
$CMD $VARIABLES "$SCRIPT" $1
And only changing the date-formatting will break it:
CMD='awk'
DATE=$(date -u)
VARIABLES="-v time=$DATE"
SCRIPT='NR>=2 {printf "%s %sn", time, $1;}'
$CMD $VARIABLES "$SCRIPT" $1
How should I escape it?
- Every kind of quoting I'm aware of doesn't work.
- Translating and inserting escaping "" before whitespace doesn't make a difference.
- Printing the variable via a function as suggested in another solution didn't work.