C Program to find if two words are anagrams (my code inside)

The program prompts the user to type two words stored in two different arrays. If the words are anagram it would print "Anagram", if not it'd print "Not Anagram". I made an array for all the alphabet letters, letter 'a' is stored as {1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ...} filling in he whole array of letters.

Then I compared both arrays, to determine if they are the same word I substracted each letter and if they are 0 (cancel out each other) they are Anagrams. Here's my code so far, I'm not sure what I'm doing wrong. I'm pretty sure there's something wrong in the Boolean function.

#include <stdio.h>
#include <stdbool.h>
#include <ctype.h>

void read_word(int counts[26])
{
    int i;
    char ch;

    printf("Enter a word: ");
    for(i=0;(ch=getchar()) != 'n' && i<30; i++)
        counts[toupper(ch)-'A']++;
}

bool equal_array(int counts1[26],int counts2[26])
{
    int i;
    bool is_anagram=false;   
    for(i=0; i<30; i++)
    {
        counts1[i]= counts1[i] - counts2[i];
        if(counts1[i] == 0)
            {
              is_anagram=true;
            }
        else
        {
            is_anagram=false;
            break;
        }

    }
   retu is_anagram;
}

int main()
{

    int first_word[26]={0};
    int second_word[26]={0};


    read_word(first_word);

    read_word(second_word);


     if( equal_array(first_word,second_word) == true)
        printf("Anagram");
    else
        printf("Not Anagram");

    retu 0;
}

I'd appreciate any help I could get.