خرید بک لینک

Vote count: 0

Give such a data frame df:

id_      val     
11111    12
12003    22
88763    19
43721    77
...

I wish to add a column diff to df, and each row of it equals to, let's say, the val in that row minus the diff in the previous row and multiply 0.4 and then add diff in the previous day:

diff = (val - diff_previousDay) * 0.4 + diff_previousDay

And the diff in the first row equals to val * 4 in that row. That is, the expected df should be:

id_      val     diff   
11111    12      4.8
12003    22      11.68
88763    19      14.608
43721    77      ...

And I have tried:

mul = 0.4
df['diff'] = df.apply(lambda row: (row['val'] - df.loc[row.name, 'diff']) * mul + df.loc[row.name, 'diff'] if int(row.name) > 0 else row['val'] * mul, axis=1) 

But got such as error:

TypeError: ("unsupported operand type(s) for -: 'float' and 'NoneType'", 'occurred at index 1')

Do you know how to solve this problem? Thank you in advance!

asked 53 secs ago

برچسب: نویسنده: استخدام کار تاريخ: جمعه 4 تير 1395 ساعت: 15:10

صفحه بندی