خرید بک لینک

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This is my PHP-Code:

<?php

include("dbcoect.php");

$abfrage = "SELECT Name, Adresse, Telefon, Nr FROM tbl_test1 WHERE 1"; $ergebnis = mysqli_query($db, $abfrage);

?> I want to show the Value of $ergebnis but it says that it could not be converted to sting. Iam a totaly begier in PHP so please help me...

asked 11 secs ago

برچسب: نویسنده: استخدام کار تاريخ: دوشنبه 31 خرداد 1395 ساعت: 15:41

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