var alph = ["a", "b", "c"];
var r = [];
for(var i = 0; i < 5; i += 1) {
r.push(alph);
}
r[0].reverse();
console.log(r);
/* Output
[ [ 'c', 'b', 'a' ],
[ 'c', 'b', 'a' ],
[ 'c', 'b', 'a' ],
[ 'c', 'b', 'a' ],
[ 'c', 'b', 'a' ] ]
*/
/* Expected output
[ [ 'c', 'b', 'a' ],
[ 'a', 'b', 'c' ],
[ 'a', 'b', 'c' ],
[ 'a', 'b', 'c' ],
[ 'a', 'b', 'c' ] ]
*/
There are arrays in an array. The first array should be reversed. I thought r[0].reverse() would do this, but instead this reverses all arrays.
Can someone explain why this happens ?
You are pushing the reference to the array, so updating one will make changes to the rest. Instead push the copy of the original array for copying array use Array#slice method.
var alph = ["a", "b", "c"];
var r = [];
for (var i = 0; i < 5; i += 1) {
r.push(alph.slice());
}
r[0].reverse();
console.log(r);
You're not creating an array of new arrays when you push onto r: you're pushing the same array onto r 5 times (it's being passed by reference, not by value). Therefore, any operation on r[0] is really updating alph, which causes all of the other references to be updated, too.
برچسب:
نویسنده: استخدام کار
تاريخ: پنجشنبه
27 خرداد
1395 ساعت: 21:03