I need to get some XML node by it's XPath, how I can do it?
I tried to use this library https://github.com/djcsdy/haxe-xpath, but something wrong https://github.com/djcsdy/haxe-xpath/issues/26
for my task xml-fast isn't good solution, because it looks "slightly worse" than XPath, I think:
js (xpath):
xml_doc.get('//project/classpaths/class[@path="' + src_path + '"]')
haxe (xml-fast):
(new Fast(xml_doc))).node.project.node.classpaths.nodes.class.filter(function (x:Fast) retu x.has.path ? x.att.path == src_path : false)
thanks
