Test each element of array for factors of 5 in C++

I had a question for the following problem (FCTRL from Codechef)

I am trying to enter in an arraysize. I am then trying to test each number in the array. The test for each number in the array is how many powers of 5 go into to it.

i.e if the number is 4617;

5^1 : 4617 ÷ 5 = 923.4, so 923 factors of 5

5^2 : 4617 ÷ 25 = 184.68, so 184 additional factors of 5

5^3 : 4617 ÷ 125 = 36.936, so 36 additional factors of 5

5^4 : 4617 ÷ 625 = 7.3872, get 7 additional factors of 5

5^5 : 4617 ÷ 3125 = 1.47744, so 1 more factor of 5

5^6 : 4617 ÷ 15625 = 0.295488, which is less than 1, so stop.

I then wish to add these up. However, ruing for an array size of 1, and the test number 1024, I get 245, when the answer is 253.

Any help is appreciated.

#include <iostream>

using namespace std;

int main()
{

int arraySize;
int answer;

cin >> arraySize;

int arr[arraySize];

    for (int i = 0; i < arraySize; i++ ){

        int number;
        cin >> number;
        arr[i] = number;
    }


    for (int j = 0; j < arraySize; j++){

        int sum = 0;
        int divisor = 5;

        while ( (arr[j]/divisor) > 0 ){

            sum += (arr[j]/divisor);

           divisor = divisor * divisor;
        }

    cout << sum << endl;

    }


retu 0;
}