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امروزدخترم رابردم دندانپزشکی .یکی ازهمکاران قدیمی به اسم خانم شریفی رادیدم خوشحال شدم ،راستش برای من فرقی نمی کنه که خاطره خوب ازهمکارام داشته باشم یانه وقتی بعدازمدتهااونهارامی بینم خوشحال میشم،بعدرف, ...ادامه مطلب

امروزدخترم رابردم دندانپزشکی .یکی ازهمکاران قدیمی به اسم خانم شریفی رادیدم خوشحال شدم ،راستش برای من فرقی نمی کنه که خاطره خوب ازهمکارام داشته باشم یانه وقتی بعدازمدتهااونهارامی بینم خوشحال میشم،بعدرف, ...ادامه مطلب

امروزدخترم رابردم دندانپزشکی .یکی ازهمکاران قدیمی به اسم خانم شریفی رادیدم خوشحال شدم ،راستش برای من فرقی نمی کنه که خاطره خوب ازهمکارام داشته باشم یانه وقتی بعدازمدتهااونهارامی بینم خوشحال میشم،بعدرف, ...ادامه مطلب

Vote count: 0 I'm reading about lambda calculus. From the end of section 2.1 here http://www.toves.org/books/lambda/: (λx.(λx.λy.x × y) 3 ((λz.x + z) 2)) 1 ⇒ (λx.λy.x × y) 3 ((λz.x + z) 2) where x = 1 ⇒ (λy.x × y) ((λz.x + z) 2) where x = 3 ⇒ x × y where x = 3 and y = (λz.x + z) 2 ⇒ x × y where x = 3 and y = x + z and z = 2 ⇒ x × y where x = 3 and y = 5 and z = 2 ⇒ 15 It says In fact, though, y should attain the value 3 rather than 5 since the first beta-reduction should plug 1 into x's spot in the expression. For this reason, a lazy parameter must preserve the current variable context with each reduction, remembering in this case that x = 3 within the expression λy.x × y but maintaining the fact that x = 1 outside the expression. But I'm confused over the order of operations during the beta reduction. There explanation is,,lambda calculus - reductions #1,lambda calculus - reductions,lambda calculus,lambda calculus tutorial,lambda calculus for dummies,lambda calculus examples,lambda calculus and functional programming,lambda calculus pdf,lambda calculus calculator,lambda calculus interpreter ...ادامه مطلب

Vote count: 0 I wrote a script that does binary merge on files within a folder in AWS S3 whenever a new file gets uploaded. I have configured the Lambda trigger on the specific bucket on Object PUT to start merging the new file in folder with the existing files in same location. I have a scenario wherein I upload multiple files to the same folder at the same time and I am trying to understand how does Lambda merge files in this scenario. Can anyone please help me understand if the Lambda drops some files and triggers only once the script or will all the file creates trigger events and Lambda invokes the script to do merge on all files without dropping any? Thanks asked 36 secs agouser2535706 Let's block ads! بخوانید, ...ادامه مطلب

Vote count: 3 Pretty short question: Is it possible to use the Symbol#to_proc shorthand (e.g. lambda(&:upcase) with the stabby lambda syntax in Ruby? For example, I can say this: p = lambda &:upcase to get a Proc in p but I can't find an equivalent using ->. This: p = -> &:upcase doesn't work, of course. edited Jun 14 '12 at 11:51 asked Jun 12 '12 at 16:03Hakan Ensari 1 Answer Vote count: 1 accepted Apparently, it is not supported. I think it has something to do with the fact that proc and lambda are actually methods, and not keywords. They support the same features that we usually associate with each and the other methods from the Enumerable module. However, -> is a special language construct which is parsed separately. I can't think of a reason why something like -> &:method shouldn't be possible, but as of now the syntax of the Ruby language simply doesn't allow it. answered Jun 13 '12 at 16:17Matheus Moreira Let's block ads! بخوانید, ...ادامه مطلب

Vote count: 0 I am trying to understand if I can use teary operators within a lambda expression. For example: public class Foo { public int ID {get; set;} public string Name {get; set;} public Address MyAdd {get; set;} } I then want to do something like this: var config = new MapperConfiguration(c => { c.CreateMap<foo, MyFoo>() .ForMember(x => x.ID, m => m.MapFrom(a => a.ID)) .ForMember(x => x.Name, m => m.MapFrom(a => a.Name)) .ForMember(x => x.Add1, m => m.MapFrom(a => (a.MyAdd != null) ? a.MyAdd.Line1 : string.Empty)); }); However I get the error: Cannot convert lambda expression to type 'string' because it is not a delegate type asked 29 secs agoJDS Let's block ads! بخوانید, ...ادامه مطلب

Vote count: 0 I have the following code let rec consume() : Async<unit> = async { ..... listA |> Seq.iter(fun i -> ..... let listB : seq<...> option = let c = getListB a b match c with | Some d -> Seq.filter(....) |> Some | None -> None Now the function getListB is converted to retu async<Seq<B>> instead of Seq<B>. So the code was converted to the following. However, the getListB blocked the execution. How to rewrite it nonblocking? Simply convert the line to let! c = getListB a b won't work because the code is in an inner lambda. let rec consume() : Async<unit> = async { ..... listA |> Seq.iter(fun i -> ..... let listB : seq<...> option = let c = getListB a b |> Async.RunSynchronously match c with | Some d -> Seq.filter(....) |> Some | None -> None asked 12 secs agodc7a9163d9 Let's block ads! بخوانید, ...ادامه مطلب

Vote count: 0 I was wondering if it's possible to pass a member function pointer into a lambda capture list? I have tried just passing it but to no avail it did not work: GetHeadline = RSSCrawler::Extract; auto headlines = client.request(methods::GET).then([RSSCrawler::*GetHeadline](http_response response) { if (response.status_code() == status_codes::OK) { auto jsonContent = response.extract_json().get(); auto outcome = GetHeadline(jsonContent); wcout << jsonContent << endl; } }); asked 38 secs agoDorkMonstuh This entry passed through the Full-Text RSS service - if this is your content and you're reading it on someone else's site, please read the FAQ at fivefilters.org/content-only/faq.php#publishers.Recommended article from FiveFilters.org: Most Labour MPs in the UK Are Revolting., ...ادامه مطلب

Vote count: 0 basically all i want to do is get my AC button working so that it clears the equation in the box, and sets it back to 0. I currently have a "C" button that clears the users last entry entered e.g 567 would become 56. I just need to add on an "AC" button that clears everything. Any ideas? from tkinter import * class Calc(): def __init__(self): self.total = 0 self.current = "" self.new_num = True self.op_pending = False self.op = "" self.eq = False def num_press(self, num): self.eq = False temp = text_box.get() temp2 = str(num) if self.new_num: self.current = temp2 self.new_num = False else: if temp2 == '.': if temp2 in temp: retu self.current = temp + temp2 self.display(self.current) def calc_total(self): self.eq = True self.current = float(self.current) if self.op_pending == True: self.do_sum() else: self.total = float(text_box.get()) def display(self, value): text_box.delete(0, END) text_box.insert(0, value) def do_sum(self): if self.op == "add": self.total += self.current if self.op == "minus": self.total -= self.current if self.op == "times": self.total *= self.current if self.op == "divide": self.total /= self.current self.new_num = True self.op_pending = False self.display(self.total) def operation(self, op): self.current = float(self.current) if self.op_pending: self.do_sum() elif not self.eq: self.total = self.current self.new_num = True self.op_pending = True self.op = op self.eq = False def cancel(self): global var self.eq = False self.curren, ...ادامه مطلب

Vote count: 0 I have two tables, Drivers and ViewDrivers that I have joined together using the following lambda expression in Entity Framework 6. var inAppDriverList = context.ViewDrivers .Select(dv => new { dv.TerminalCode, dv.EmployeeId }) .Join( context.Drivers, d => d.EmployeeId, dv => dv.EmployeeId, (d, dv) => new { d, dv } ) .OrderBy(dv => dv.TerminalCode) .GroupBy(dv => dv.TerminalCode) .ToList(); It does give me the data that I am expecting to get, but I when I try to Sort and Group the list by the TerminaleCode using GroupBy and OrderBy, I cannot get it to work correctly. I have tried everything I can think of, with no luck. I am only having this issue when I am trying to sort a joined table so I am guessing there is something small that I am missing. I would greatly appreciate any help in getting those statements to Group and Sort by the TerminalCode field. asked 37 secs agomichaelk46 Let's block ads! بخوانید, ...ادامه مطلب

Vote count: 0 I created 4 Lambda functions to process information that will be written into a MySQL table. the first three function just select, insert and update a MYSQL table record respectively. I then created a 4th function to accept the record detail as part of the event parameter. This function will first try to select the record by invoking the first lambda function and if it finds it, will update the record on the table using the update lambda function. If it does not find it, it will invoke the insert function to add the record. I am using pool.query on the 3 functions that manipulates the MySQL table. I am also using lambda.invoke to call those three functions from the 4th function. I was able to successfully test the 4th function locally by passing the record details as parameter and it was able to successfully call the three Lambda function and update the mySQL table record. The problem that I am having is that when I upload the function in AWS Lambda, it does not invoke any of the three functions. I am not seeing any errors in the log so I don't know how to check where the problem is. Here's ,y code that invokes the other functions: exports.handler = (event, context, callback) => { var err = null; var payload = { qryString : event.qryString, record: event.updaterecord, dbConfigPool : event.dbConfigPool } var params = { FunctionName: 'getInventory', Payload: JSON.stringify(payload) } console.log(' before invoke ' + JSON.stringify(params) ) lambda.invoke(params, function(err, data) { console.log(' aftr invoke ' + JSON.stringify(params) ) if (err) { console.log('err ' + err, err.stack); // an error occurred event.message = err + ' query error'; } else { console.log('success' + JSON.stringify(data)); console.log(' status code ' + JSON.stringify(data.StatusCode)); console.log(' Payload ' + JSON.stringify(JSON.parse(data.Payload))); var rowsTemp = JSON.parse(data, ...ادامه مطلب

Vote count: 0 I've created a trigger in my AWS CodeCommit repositories which runs a Lambda function whenever it is triggered. The Lambda function calls a script at my development server to perform a git pull. So far so good. The problem is that I need to pass the name or ID of the repository that sets off the trigger to the dev machine so I can git pull the correct repository. My question then, is how do you call the name or id of the repository which triggered the Lambda function within the Lambda function? My Lambda function is written in Python I've taken a look at the Lambda documentation at http://docs.aws.amazon.com/lambda/latest/dg/welcome.html but there is no mention of CodeCommit. This is probably because CodeCommit triggers are quite new - only a few months old. There is some documentation of event sources at http://docs.aws.amazon.com/lambda/latest/dg/eventsources.html . I followed the tutorial at - http://docs.aws.amazon.com/codecommit/latest/userguide/how-to-notify-lambda.html to create the Lambda function. Any help would be much appreciated! asked 1 min agoJames Jones Let's block ads! بخوانید, ...ادامه مطلب

Vote count: 0 I am unable to get a distinct list of 'Order' from my Lambda query. Even though am using the keyword Distinct() it is still retuing repeated select list item. public ActionResult Index() { var query = _dbContext.Orders .ToList() .Select(x => new SelectListItem { Text = x.OrderID.ToString(), Value = x.ShipCity }) .OrderBy(y => y.Value); ViewBag.DropDownValues = new SelectList(query, "Text", "Value"); retu View(); } Any suggestions please? asked 1 min agoKevin Let's block ads! بخوانید, ...ادامه مطلب

Vote count: 0 Could someone help or guide me through what I should do better in order for this to work? I changed the number of inputs to 2 and generated some random data, "x1" and "x2" (one number to be added to another). The idea is to use variables "add" and "mul" as the real output and base the cost (variable "Y") off of that, but I'm having trouble manipulating the data so it inputs properly. I tried to make another variable with x = tf.Variable([100 * np.random.random_sample([100]), 100 * np.random.random_sample([100])) and a few other alteative ways, but that caused errors. Also, if there's anything else wrong in my code, please critique it! Anything helps. Thank you. ''' A Recurrent Neural Network implementation example using TensorFlow Library. Author: ********* ''' import numpy as np import tensorflow as tf from tensorflow.models.n import n, n_cell # import matplotlib.pyplot as plt # from mpl_toolkits.mplot3d import Axes3D # Parameters training_iters = 1000 n_epochs = 1000 batch_size = 128 display_step = 100 leaing_rate = 0.001 n_observations = 100 n_input = 2 # Input data (Num + Num) n_steps = 28 # timesteps n_hidden_1 = 256 # 1st layer number of features n_hidden_2 = 256 # 2nd layer number of features n_classes = 1 # Output X = tf.placeholder("float", [None, n_input]) X1 = tf.placeholder(tf.float32) X2 = tf.placeholder(tf.float32) Y = tf.placeholder(tf.float32) # Random input data x1 = 100 * np.random.random_sample([100,]) x2 = 100 * np.random.random_sample([100,]) add = tf.add(x1, x2) mul = tf.mul(X1, X2) weights = { 'hidden1': tf.Variable(tf.random_normal([n_input, n_hidden_1])), #'hidden2': tf.Variable(tf.random_normal([n_hidden_1, n_hidden_2])), 'out': tf.Variable(tf.random_normal([n_hidden_1, n_classes])) } biases = { 'hidden1': tf.Variable(tf.random_normal([n_hidden_1])), #'hidden2': tf.Variable(tf.random_normal([n_hidden_2])), 'out': tf.Variable(tf.r, ...ادامه مطلب