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متن مرتبط با «lambda calculus» در سایت back soft نوشته شده است

AWS invoke a lambda function by another lambda function gives time out output

  • امروزدخترم رابردم دندانپزشکی .یکی ازهمکاران قدیمی به اسم خانم شریفی رادیدم خوشحال شدم ،راستش برای من فرقی نمی کنه که خاطره خوب ازهمکارام داشته باشم یانه وقتی بعدازمدتهااونهارامی بینم خوشحال میشم،بعدرف, ...ادامه مطلب

  • python keyerror with dataframe loc and apply lambda

  • امروزدخترم رابردم دندانپزشکی .یکی ازهمکاران قدیمی به اسم خانم شریفی رادیدم خوشحال شدم ،راستش برای من فرقی نمی کنه که خاطره خوب ازهمکارام داشته باشم یانه وقتی بعدازمدتهااونهارامی بینم خوشحال میشم،بعدرف, ...ادامه مطلب

  • Lambda calculus - evaluating these lazy parameters

  • Vote count: 0 I'm reading about lambda calculus. From the end of section 2.1 here http://www.toves.org/books/lambda/: (λx.(λx.λy.x × y) 3 ((λz.x + z) 2)) 1 ⇒ (λx.λy.x × y) 3 ((λz.x + z) 2) where x = 1 ⇒ (λy.x × y) ((λz.x + z) 2) where x = 3 ⇒ x × y where x = 3 and y = (λz.x + z) 2 ⇒ x × y where x = 3 and y = x + z and z = 2 ⇒ x × y where x = 3 and y = 5 and z = 2 ⇒ 15 It says In fact, though, y should attain the value 3 rather than 5 since the first beta-reduction should plug 1 into x's spot in the expression. For this reason, a lazy parameter must preserve the current variable context with each reduction, remembering in this case that x = 3 within the expression λy.x × y but maintaining the fact that x = 1 outside the expression. But I'm confused over the order of operations during the beta reduction. There explanation is,,lambda calculus - reductions #1,lambda calculus - reductions,lambda calculus,lambda calculus tutorial,lambda calculus for dummies,lambda calculus examples,lambda calculus and functional programming,lambda calculus pdf,lambda calculus calculator,lambda calculus interpreter ...ادامه مطلب

  • AWS Lambda - Multiple objects uploaded to the same folder at same time

  • Vote count: 0 I wrote a script that does binary merge on files within a folder in AWS S3 whenever a new file gets uploaded. I have configured the Lambda trigger on the specific bucket on Object PUT to start merging the new file in folder with the existing files in same location. I have a scenario wherein I upload multiple files to the same folder at the same time and I am trying to understand how does Lambda merge files in this scenario. Can anyone please help me understand if the Lambda drops some files and triggers only once the script or will all the file creates trigger events and Lambda invokes the script to do merge on all files without dropping any? Thanks asked 36 secs agouser2535706 Let's block ads! بخوانید, ...ادامه مطلب

  • Difference between `->` and `lambda` in ruby [duplicate]

  • Vote count: 3 Pretty short question: Is it possible to use the Symbol#to_proc shorthand (e.g. lambda(&:upcase) with the stabby lambda syntax in Ruby? For example, I can say this: p = lambda &:upcase to get a Proc in p but I can't find an equivalent using ->. This: p = -> &:upcase doesn't work, of course. edited Jun 14 '12 at 11:51 asked Jun 12 '12 at 16:03Hakan Ensari 1 Answer Vote count: 1 accepted Apparently, it is not supported. I think it has something to do with the fact that proc and lambda are actually methods, and not keywords. They support the same features that we usually associate with each and the other methods from the Enumerable module. However, -> is a special language construct which is parsed separately. I can't think of a reason why something like -> &:method shouldn't be possible, but as of now the syntax of the Ruby language simply doesn't allow it. answered Jun 13 '12 at 16:17Matheus Moreira Let's block ads! بخوانید, ...ادامه مطلب

  • Can I use ternary operator with a lambda expression?

  • Vote count: 0 I am trying to understand if I can use teary operators within a lambda expression. For example: public class Foo { public int ID {get; set;} public string Name {get; set;} public Address MyAdd {get; set;} } I then want to do something like this: var config = new MapperConfiguration(c => { c.CreateMap<foo, MyFoo>() .ForMember(x => x.ID, m => m.MapFrom(a => a.ID)) .ForMember(x => x.Name, m => m.MapFrom(a => a.Name)) .ForMember(x => x.Add1, m => m.MapFrom(a => (a.MyAdd != null) ? a.MyAdd.Line1 : string.Empty)); }); However I get the error: Cannot convert lambda expression to type 'string' because it is not a delegate type asked 29 secs agoJDS Let's block ads! بخوانید, ...ادامه مطلب

  • Call async method in an inner lambda?

  • Vote count: 0 I have the following code let rec consume() : Async<unit> = async { ..... listA |> Seq.iter(fun i -> ..... let listB : seq<...> option = let c = getListB a b match c with | Some d -> Seq.filter(....) |> Some | None -> None Now the function getListB is converted to retu async<Seq<B>> instead of Seq<B>. So the code was converted to the following. However, the getListB blocked the execution. How to rewrite it nonblocking? Simply convert the line to let! c = getListB a b won't work because the code is in an inner lambda. let rec consume() : Async<unit> = async { ..... listA |> Seq.iter(fun i -> ..... let listB : seq<...> option = let c = getListB a b |> Async.RunSynchronously match c with | Some d -> Seq.filter(....) |> Some | None -> None asked 12 secs agodc7a9163d9 Let's block ads! بخوانید, ...ادامه مطلب

  • Passing function pointer into lambda capture list

  • Vote count: 0 I was wondering if it's possible to pass a member function pointer into a lambda capture list? I have tried just passing it but to no avail it did not work: GetHeadline = RSSCrawler::Extract; auto headlines = client.request(methods::GET).then([RSSCrawler::*GetHeadline](http_response response) { if (response.status_code() == status_codes::OK) { auto jsonContent = response.extract_json().get(); auto outcome = GetHeadline(jsonContent); wcout << jsonContent << endl; } }); asked 38 secs agoDorkMonstuh This entry passed through the Full-Text RSS service - if this is your content and you're reading it on someone else's site, please read the FAQ at fivefilters.org/content-only/faq.php#publishers.Recommended article from FiveFilters.org: Most Labour MPs in the UK Are Revolting., ...ادامه مطلب

  • Entity Framework 6 Using Lambda GroupBy on a joined table

  • Vote count: 0 I have two tables, Drivers and ViewDrivers that I have joined together using the following lambda expression in Entity Framework 6. var inAppDriverList = context.ViewDrivers .Select(dv => new { dv.TerminalCode, dv.EmployeeId }) .Join( context.Drivers, d => d.EmployeeId, dv => dv.EmployeeId, (d, dv) => new { d, dv } ) .OrderBy(dv => dv.TerminalCode) .GroupBy(dv => dv.TerminalCode) .ToList(); It does give me the data that I am expecting to get, but I when I try to Sort and Group the list by the TerminaleCode using GroupBy and OrderBy, I cannot get it to work correctly. I have tried everything I can think of, with no luck. I am only having this issue when I am trying to sort a joined table so I am guessing there is something small that I am missing. I would greatly appreciate any help in getting those statements to Group and Sort by the TerminalCode field. asked 37 secs agomichaelk46 Let's block ads! بخوانید, ...ادامه مطلب

  • AWS Lambda Invoke does not execute the lambda function

  • Vote count: 0 I created 4 Lambda functions to process information that will be written into a MySQL table. the first three function just select, insert and update a MYSQL table record respectively. I then created a 4th function to accept the record detail as part of the event parameter. This function will first try to select the record by invoking the first lambda function and if it finds it, will update the record on the table using the update lambda function. If it does not find it, it will invoke the insert function to add the record. I am using pool.query on the 3 functions that manipulates the MySQL table. I am also using lambda.invoke to call those three functions from the 4th function. I was able to successfully test the 4th function locally by passing the record details as parameter and it was able to successfully call the three Lambda function and update the mySQL table record. The problem that I am having is that when I upload the function in AWS Lambda, it does not invoke any of the three functions. I am not seeing any errors in the log so I don't know how to check where the problem is. Here's ,y code that invokes the other functions: exports.handler = (event, context, callback) => { var err = null; var payload = { qryString : event.qryString, record: event.updaterecord, dbConfigPool : event.dbConfigPool } var params = { FunctionName: 'getInventory', Payload: JSON.stringify(payload) } console.log(' before invoke ' + JSON.stringify(params) ) lambda.invoke(params, function(err, data) { console.log(' aftr invoke ' + JSON.stringify(params) ) if (err) { console.log('err ' + err, err.stack); // an error occurred event.message = err + ' query error'; } else { console.log('success' + JSON.stringify(data)); console.log(' status code ' + JSON.stringify(data.StatusCode)); console.log(' Payload ' + JSON.stringify(JSON.parse(data.Payload))); var rowsTemp = JSON.parse(data, ...ادامه مطلب

  • Get name of Amazon Web Services Codecommit Repository in triggered Lambda function

  • Vote count: 0 I've created a trigger in my AWS CodeCommit repositories which runs a Lambda function whenever it is triggered. The Lambda function calls a script at my development server to perform a git pull. So far so good. The problem is that I need to pass the name or ID of the repository that sets off the trigger to the dev machine so I can git pull the correct repository. My question then, is how do you call the name or id of the repository which triggered the Lambda function within the Lambda function? My Lambda function is written in Python I've taken a look at the Lambda documentation at http://docs.aws.amazon.com/lambda/latest/dg/welcome.html but there is no mention of CodeCommit. This is probably because CodeCommit triggers are quite new - only a few months old. There is some documentation of event sources at http://docs.aws.amazon.com/lambda/latest/dg/eventsources.html . I followed the tutorial at - http://docs.aws.amazon.com/codecommit/latest/userguide/how-to-notify-lambda.html to create the Lambda function. Any help would be much appreciated! asked 1 min agoJames Jones Let's block ads! بخوانید, ...ادامه مطلب

  • C# MVC Lambda Distinct not working

  • Vote count: 0 I am unable to get a distinct list of 'Order' from my Lambda query. Even though am using the keyword Distinct() it is still retuing repeated select list item. public ActionResult Index() { var query = _dbContext.Orders .ToList() .Select(x => new SelectListItem { Text = x.OrderID.ToString(), Value = x.ShipCity }) .OrderBy(y => y.Value); ViewBag.DropDownValues = new SelectList(query, "Text", "Value"); retu View(); } Any suggestions please? asked 1 min agoKevin Let's block ads! بخوانید, ...ادامه مطلب

  • Linq to SQL added a Lambda .Join geting AnonymousType#1' does not contain a definition and no extension method

  • Vote count: 0 As join as I add in a Lambda .Join I am getting problem with my linq lambda .Where(.. .Where(z => z.Inact_ind == "N" && z.Wwid != null) That is fine UNTIL I add in .Join above it. eg .Join(Rpm_scrty_emp_info, z => z.Wwid, ei => ei.Wwid, (z, ei) => new{z,ei}) linq query (Linqpad , so Rpm_scrty_rpm_usrs is essentially the same as dbcontext dbset) var queryAllUsers = Rpm_scrty_rpm_usrs .Join(Rpm_scrty_emp_info, z => z.Wwid, ei => ei.Wwid, (z, ei) => new{z,ei}) .Where(z => z.Inact_ind == "N" && z.Wwid != null) .AsEnumerable() .Select(z => new rpm_scrty_rpm_usr() { usr_id = z.Usr_id, usr_lnm = z.Usr_lnm, usr_pwd = z.Usr_pwd, usr_fnm = z.Usr_fnm, wwid = z.Wwid, apprvr_wwid = z.Apprvr_wwid, chg_dtm = z.Chg_dtm, chg_usr_id = z.Chg_usr_id, dflt_ste_id = z.Dflt_ste_id, cre_dtm = z.Cre_dtm, cre_usr_id = z.Cre_usr_id, lst_pwd_chg_dtm = z.Lst_pwd_chg_dtm, lst_accs_dtm = z.Lst_accs_dtm, email_id = z.Email_id, inact_ind = z.Inact_ind, salt = z.Salt, tel = z.Tel //}); }) .ToList(); Poco class public class rpm_scrty_rpm_usr { public string usr_id { get; set; } public string usr_fnm { get; set; } public string usr_lnm { get; set; } public string usr_pwd { get; set; } public string email_id { get; set; } public string wwid { get; set; } public string tel { get; set; } public int dflt_ste_id { get; set; } public DateTime? lst_pwd_chg_dtm { get; set; } public DateTime? lst_accs_dtm { get; set; } public string apprvr_wwid { get; set; } public string inact_ind { get; set; } public, ...ادامه مطلب

  • Is there any difference between noexcept and empty throw specifiaction for an lambda expression?

  • Vote count: 1 Given an example: double values[] {2.5, -3.5, 4.5, -5.5, 6.5, -7.5}; std::vector<double> squares(std::end(values) - std::begin(values)); std::transform(std::begin(values), std::end(values), std::begin(values), std::begin(squares), [](double x1, double x2) throw() { retu x1 * x2; }); 1) Is this functional equivalent to: [](double x1, double x2) noexcept { retu x1 * x2; }) ? 2) Is there a convincible reason, why should I mark such expression (or similar basic expresions) with either modifiers or in this case, it is better to leave it and simply don't bother? asked 3 mins agoGrzegorz Szpetkowski Let's block ads! بخوانید, ...ادامه مطلب

  • What is this lambda expression with Unity Resolver doing

  • Vote count: 1 Looking through someone else's code I found this line of code: protected IDirectIp Iridium => _resolver.Resolve<IDirectIp>(); I was confused seeing a lambda (=>) instead of an equal sign (=). The dependency injection library is Unity, is this syntax specific to Unity? Could anyone explain what this expression is doing? asked 1 min agoBrian Ogden Let's block ads! بخوانید, ...ادامه مطلب

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